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Thread: Random watch thread 2

  1. #9511

    Random watch thread 2

    Quote Originally Posted by skywatch View Post
    The problem is that X, Y and Z are all variables, and we can't solve a three variable equation without additional equations to cross-reference the variables. In fact, we end up with a saddle shaped curve depicting a Reimanian surface, and the triangulation of variables would shift along that curve with relationships adjusted by cost of the watch. This becomes a 4-dimensional curve and it's like solving a 3-body gravitational problem, which can only be accomplished within error ranges set by initial conditions. I'll need to go set up some simulations on my Beowulf array, and I'll get back to you in a week of so, when the modeling is complete.


    I get what you mean though.

    Basically I’m estimating £170 for a service of an ETA 2824. Watch a is about £380, watch b is about £550

    Watch a



    watch b


    Watch porn for hayday



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  2. #9512
    I'd select the serviced watch in better condition. Even after servicing the older watch, it would not be in the same condition as the watch that started out in better condition.


    Quote Originally Posted by whatmeworry View Post
    Not sure if this really the right place for this, but didn’t feel it was worth a thread on its own.

    Would you buy:

    a) an automatic watch in honest used condition and 8 years old without having been serviced for price x

    Or

    b) same watch, 2 years old, much better condition for price z

    Given the price of a service is roughly y, then x+y=z


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  4. #9513
    Porous Membrane skywatch's Avatar
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    Quote Originally Posted by whatmeworry View Post

    I get what you mean though.
    Basically I’m estimating £170 for a service of an ETA 2824. Watch a is about £380, watch b is about £550
    Watch a
    watch b
    Sorry my sense of humor might not translate well into text.
    Seeing the variables replaced by constants, I vote Watch B, the newer one.
    I am usually happy to service a watch that has personal history or family heirlooms.
    The service costs seem rarely justified for a new purchase that has no specific rarity or personal meaning.
    For my "affordables" I am fine just letting them wear down into gentle senility, as the service is more expensive than a replacement.
    Too many watches, not enough wrists.

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  6. #9514
    MWC is that my watch's Avatar
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    just to be contrary I would go WATCH A
    sharky
    one of the most original good guys their was never anything but a true friend "the daito to my shoto"
    rest easy good buddy
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  7. #9515
    Quote Originally Posted by skywatch View Post
    Sorry my sense of humor might not translate well into text.
    Seeing the variables replaced by constants, I vote Watch B, the newer one.
    I am usually happy to service a watch that has personal history or family heirlooms.
    The service costs seem rarely justified for a new purchase that has no specific rarity or personal meaning.
    For my "affordables" I am fine just letting them wear down into gentle senility, as the service is more expensive than a replacement.
    Same here
    And yeah I think b feels like the way to go. I’d hate to shell out for a service on a watch I then flipped.


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  8. #9516
    Quote Originally Posted by is that my watch View Post
    just to be contrary I would go WATCH A
    Rebel!


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  9. #9517
    deadhead hayday's Avatar
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    Quote Originally Posted by whatmeworry View Post

    Watch porn for hayday



    Sent from my iPhone using Tapatalk

    Once in awhile you get shown the light in the strangest of places if you look at it right.

  10. #9518
    deadhead hayday's Avatar
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    Quote Originally Posted by skywatch View Post
    The problem is that X, Y and Z are all variables, and we can't solve a three variable equation without additional equations to cross-reference the variables. In fact, we end up with a saddle shaped curve depicting a Reimanian surface, and the triangulation of variables would shift along that curve with relationships adjusted by cost of the watch. This becomes a 4-dimensional curve and it's like solving a 3-body gravitational problem, which can only be accomplished within error ranges set by initial conditions. I'll need to go set up some simulations on my Beowulf array, and I'll get back to you in a week of so, when the modeling is complete.
    I recognize the words you used but I have no idea what the eff you just said.
    Once in awhile you get shown the light in the strangest of places if you look at it right.

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  12. #9519
    Porous Membrane skywatch's Avatar
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    Quote Originally Posted by hayday View Post
    I recognize the words you used but I have no idea what the eff you just said.
    Too many watches, not enough wrists.

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  14. #9520
    Super Member Raza's Avatar
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    Quote Originally Posted by whatmeworry View Post
    Not sure if this really the right place for this, but didn’t feel it was worth a thread on its own.

    Would you buy:

    a) an automatic watch in honest used condition and 8 years old without having been serviced for price x

    Or

    b) same watch, 2 years old, much better condition for price z

    Given the price of a service is roughly y, then x+y=z


    Sent from my iPhone using Tapatalk
    Option B. I’d even pay a slight premium to avoid having the watch have to go immediately out for service.
    Read my latest IWL blog entry! An Ode To Rule Breaking

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