Random watch thread 2

[mlcor]

https://www.hodinkee.com/articles/om...00-introducing

Looks like Omega copied my steez and put the SM300 on a iyonk-style strap.

I don’t like the new look as much as mine, I think the white balances the dial better and I prefer the numeral font on mine. But I’m intrigued by the bracelet—the article claims it tapers to 16mm, which I don’t believe the one mine has does (I’ll have to check). I wonder if a bracelet swap is possible and again, how much it would cost to buy the new bracelet and have the outer links brushed, and how much I could sell my old style bracelet for.

I like the look, although not totally sure about the lollipop seconds hand thingie. I also wonder, at 13.85mm thick, if a bracelet that tapers all the way to 16mm would make the watch a bit top heavy? An academic point for me, as I'm not in the market...

[whatmeworry]

I like the look, although not totally sure about the lollipop seconds hand thingie. I also wonder, at 13.85mm thick, if a bracelet that tapers all the way to 16mm would make the watch a bit top heavy? An academic point for me, as I'm not in the market...

I find the numerals a bit too cramped in as well


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[geoffbot]

Not a fan of they ref at all I'm afraid

[Raza]

I like the look, although not totally sure about the lollipop seconds hand thingie. I also wonder, at 13.85mm thick, if a bracelet that tapers all the way to 16mm would make the watch a bit top heavy? An academic point for me, as I'm not in the market...

Despite being a bit thick, it’s not that heavy of a watch, really. With a full bracelet on both, the Seamaster (my model, anyway) is only 10 grams heavier than a Submariner. 79.3 grams for the head only. According to a thread I found on TRF, the Submariner is 81g for the head only. So even with a 16mm taper, it should wear fine.

But I checked my bracelet and it definitely does not taper to 16mm. I’ve misplaced my calipers at the moment, but I’d guess the links taper to 18mm, but the clasp itself goes back to 20 or 21mm.

[whatmeworry]

Not sure if this really the right place for this, but didn’t feel it was worth a thread on its own.

Would you buy:

a) an automatic watch in honest used condition and 8 years old without having been serviced for price x

Or

b) same watch, 2 years old, much better condition for price z

Given the price of a service is roughly y, then x+y=z


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[Mediocre]

Not sure if this really the right place for this, but didn’t feel it was worth a thread on its own.

Would you buy:

a) an automatic watch in honest used condition and 8 years old without having been serviced for price x

Or

b) same watch, 2 years old, much better condition for price z

Given the price of a service is roughly y, then x+y=z


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If the equation is accurate, the newer one. There is always risk in getting a watch serviced, even if the risk is minimal for things like scratches. Service also takes time, so the newer one can be worn and enjoyed now. The older one will arrive...then be away for awhile for service

I always factor in a service on anything 5+ years old, and it does impact what I buy and offer

[hayday]

Not sure if this really the right place for this, but didn’t feel it was worth a thread on its own.

Would you buy:

a) an automatic watch in honest used condition and 8 years old without having been serviced for price x

Or

b) same watch, 2 years old, much better condition for price z

Given the price of a service is roughly y, then x+y=z


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I'm here for watch porn, not math.

[tribe125]

If the equation is accurate, the newer one. There is always risk in getting a watch serviced, even if the risk is minimal for things like scratches. Service also takes time, so the newer one can be worn and enjoyed now. The older one will arrive...then be away for awhile for service

I always factor in a service on anything 5+ years old, and it does impact what I buy and offer

This.

‘Much better condition’ would be one deciding factor. Also, with the older watch I’d be conscious of the pending need for service, and I’d rather have five years or so without having to think about it.

[skywatch]

Would you buy:
a) an automatic watch in honest used condition and 8 years old without having been serviced for price x
Or
b) same watch, 2 years old, much better condition for price z
Given the price of a service is roughly y, then x+y=z

The problem is that X, Y and Z are all variables, and we can't solve a three variable equation without additional equations to cross-reference the variables. In fact, we end up with a saddle shaped curve depicting a Reimanian surface, and the triangulation of variables would shift along that curve with relationships adjusted by cost of the watch. This becomes a 4-dimensional curve and it's like solving a 3-body gravitational problem, which can only be accomplished within error ranges set by initial conditions. I'll need to go set up some simulations on my Beowulf array, and I'll get back to you in a week of so, when the modeling is complete.

[whatmeworry]

I'm here for watch porn, not math.

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